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hipolito · Feb 18th, 2005, 4:59 AM

This is what I did:

void routine()
char value;
printf("\nEnter a value: ");
scanf("%d", &value);
if (isalpha(ponto))
printf("\nLetter");
else
printf("\nNumber");
os_exit(0);

Just what Infinite did, well even letter or a number shows Number on my screen... I guess difining it as char, whaever I type will aways be a string...

and Hockeyman, the program compiles just well, and the error shown is when I define the value as int and type a letter... so I must use the "%d" on scanf to get it work for both letters and number, but still the if clause will always go on ELSE option...

Feb 18th, 2005, 4:59 AM	#10
hipolito Programmer Join Date: Feb 2005 Posts: 41 Rep Power: 0	Well here it goes! This is what I did: void routine() char value; printf("\nEnter a value: "); scanf("%d", &value); if (isalpha(ponto)) printf("\nLetter"); else printf("\nNumber"); os_exit(0); Just what Infinite did, well even letter or a number shows Number on my screen... I guess difining it as char, whaever I type will aways be a string... and Hockeyman, the program compiles just well, and the error shown is when I define the value as int and type a letter... so I must use the "%d" on scanf to get it work for both letters and number, but still the if clause will always go on ELSE option...