Programming Forums - View Single Post

Jared · Feb 17th, 2005, 6:50 PM

For now, I'm just using this little check.

if(n == 8) a = 3;
else a = log(n)/log(2);

I still don't know why it does not return the right value when n = 8. I'm going to try it in Linux and see if it works right there.

Feb 17th, 2005, 6:50 PM	#2
Jared Newbie Join Date: Feb 2005 Posts: 2 Rep Power: 0	For now, I'm just using this little check. (Toggle Plain Text) if(n == 8) a = 3; else a = log(n)/log(2); if(n == 8) a = 3; else a = log(n)/log(2); I still don't know why it does not return the right value when n = 8. I'm going to try it in Linux and see if it works right there.