Leav

actualey mjordan, thats not how to solve an equation of the 5th power...
because the answer can most certanly be a non-integer.

what with the basic math they are teaching us at school, all i know is how to solve equations from the 2nd dimension:

ax^2+bx+c=0

x: [-b(+-)sqrt(b^2-4ac)]/2a

hope that made sense

Ooble

At least make it look funky:
x = -b ± √(b² - 4ac)
. . . . . . . . 2a

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