{

     do printf ("Welcome and please follow instruction to order/n");
     printf ("enter your table number 1-25");  //---> it says syntax error before printf here
   
  scanf ("%d", tablenumber);
     if (tablenumber > 25); 
     return tablenumber;
    {
  ______________________________________
              {
                     bill = (6.50 + .50) *nopizzas;
                     printf ("your order will cost",bill); 
return 0;
}}}}}}
// C:\Users\Digit0ljedi\Desktop\sdgf\Makefile.win [Build Error] n\make.exe: *** ["order form.o"] Error 1 
//is this a a computer error or still code

#include <stdio.h>
#include <stdlib.h>
#include <math.h>         

int main()        
{
int *tablenumber;
char *pizzabase;
char *pizza;
char *topping;
int *nopizza;
float bill;
float a = 0.50;
float b = 0.50;
float c = 3.50;
float d = 3.70;
float e = 4.00;
float f = 3.40;
float g = 0.75;
float h = 1.00;
float i = 0.45;

{
      
printf("|---------------------------------|\n");
printf("|Max shaws pizza ordering form    |\n");
printf("|25 June  Version 1.0             |\n");
printf("|---------------------------------|\n\n");


    {
                printf ("enter what pizza base you would like choose between\n");
                printf ("Thin and Crispy(a) or thick and cheesy(b)\n");
                do scanf("%c",&*pizzabase);
                while (*pizzabase==a);
                while (*pizzabase==b);
                
               
    {

                

printf ("please choose a pizza\n");
printf ("vegetarian (c), Meatfeast (d), Seafood (e), Cheese and Tomato (f)\n");
do scanf("%c",&*pizza);
while (*pizza==c);
while (*pizza==d);
while (*pizza==e);
while (*pizza==f);


{
      
       printf ("please choose an extra topping\n");
       printf ("anchovies (g), peppers (h), none (i)\n");
       do scanf("%c",&*topping);
       while (*topping==g);
       while (*topping==h);
       while (*topping==i);
       
       {
              printf ("how many pizzas wuold you like between 1 -10?");
              do scanf ("%d", &*nopizza);
              while (*nopizza >=11);
              while (*nopizza<=0);
              {
                     bill = (*pizzabase + *pizza + *topping) * *nopizza;
                     printf ("your order will \n"); 
                     printf("Total = %d",bill); 
                                          
                            {
system ("pause");
return *tablenumber;
return *pizzabase;
return *pizza;
return *topping;
return *nopizza;
return bill;
return 0;
}}}}}}}}

/* Simple do-while example.
 *
 * do-while loops are categorized by their behavior of
 * always executing the body of the loop once before a condition
 * is tested. If the condition listed at the end of the loop
 * is evaluated to true, then the loop will continue. Otherwise,
 * it will terminate.
 */
 
#include <stdio.h>
#include <string.h>
 
char *passwd = "apple";
 
#define BUFFSIZE 256
 
/* Ignore this function. It just removes the
 * newline character read in by fgets from
 * the string.
 */
char *chomp( char *str ) {
    char *end = str + strlen( str ) - 1;
 
    if ( *end == '\n' )
        *end = '\0';
 
    return str;
}
 
int main( void ) {
    char buffer[BUFFSIZE];
 
    /* The action that we want to occur regardless
     * of the condition is the prompt for the password
     * and the actual retrieval of the password.
     * Next, once we have it, we compare
     * the input to the know password above ("apple");
     * If the passwords match (and strcmp() returns 0
     * when the strings it is comparing are equivalent),
     * then the condition will evaluate to false
     * and the loop will continue. Otherwise, strcmp()
     * will return a value either greater than 1 or
     * less than -1 (both of which evaluate to true),
     * and the loop will continue again and re-ask for
     * the password.
     */
    do {
        printf( "password: " );
        fgets( buffer, BUFFSIZE, stdin );
    } while ( strcmp( chomp( buffer ), passwd ) );
 
    puts( "Password accepted. Welcome 007" );
    return 0;
}