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#1 | |
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Orthogonal array calculation
I am having a bit of a trouble understanding orthogonal array calculation. I am trying to understand the following example given by the lecturer: (not exact words, just what I managed to jot down)
a function that takes 20 inputs of true and false values will have a: single mode calculation of: 2x20 double mode calculation: (20x(20-1)x2)x4 I think I managed to understand the single mode because there are 2 values and 20 parameters. I also think I understand some of the double mode. 20x because there are 20 input parameters and the x2 because there are 2 values. The part i don't understand about the double is 20-1 and x4.
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#2 |
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Re: Orthogonal array calculation
You'll have to ask your lecturer. Your notes are not complete enough to even allow an understanding of your question, let alone give an answer.
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#3 |
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Re: Orthogonal array calculation
The only thing that I know about orthogonality is that two vectors are orthogonal if, when multiplied, they equal 0. Lol. Hope that helps. But I doubt it does.
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#4 |
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Re: Orthogonal array calculation
its not only vectors, anything can be orthgonal
orthogonal only means that the objects are at right angles to each other I searched google came across these websites which may be of help http://mathworld.wolfram.com/OrthogonalArray.html http://www.research.att.com/~njas/doc/OA.html Last edited by mark; May 12th, 2008 at 7:15 PM. |
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