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Sane · May 3rd, 2008, 5:33 PM

Wait, what? Hold on a tick. Divide by 4?

If you just want the number of lists, then use the len function...

len(abspirlist)

That will give you 3 in my example.

And in the code you posted, don't do:

del abspirlist[:dice]

Reassign your array in the same manner I showed you in my second post.

x = x[a:]   # Will keep all elements from the a'th element to the end
x = x[:a]   # Will keep all elements until the a'th element

May 3rd, 2008, 5:33 PM	#6
Sane Programming Guru Join Date: Apr 2005 Posts: 1,788 Rep Power: 5	Re: Are nested lists indestructable? Wait, what? Hold on a tick. Divide by 4? If you just want the number of lists, then use the len function... (Toggle Plain Text) len(abspirlist) len(abspirlist) That will give you 3 in my example. And in the code you posted, don't do: (Toggle Plain Text) del abspirlist[:dice] del abspirlist[:dice] Reassign your array in the same manner I showed you in my second post. (Toggle Plain Text) x = x[a:] # Will keep all elements from the a'th element to the end x = x[:a] # Will keep all elements until the a'th element x = x[a:] # Will keep all elements from the a'th element to the end x = x[:a] # Will keep all elements until the a'th element __________________ Waterloo's Canadian Computing Competition (CCC) - Stage 2 Problems, Solutions, and Test Data