Programming Forums - View Single Post

Sane · May 3rd, 2008, 4:43 PM

So if you had:

abspirlist = [['name', 'att', 'def', 1], 
              ['name', 'att', 'def', 1], 
              ['name', 'att', 'def', 1]]

You want the number 12, for the total number of nested elements?

You can do that with a little fancy work, by generating a list of lengths (in this case: [4, 4, 4]).

Then feeding it to the sum function (sum([4,4,4]) evaluates 12).

Combining these two ideas gives us:

(Toggle Plain Text)

sum((len(x) for x in abspirlist))

May 3rd, 2008, 4:43 PM	#4
Sane Programming Guru Join Date: Apr 2005 Posts: 1,788 Rep Power: 5	Re: Are nested lists indestructable? So if you had: (Toggle Plain Text) abspirlist = [['name', 'att', 'def', 1], ['name', 'att', 'def', 1], ['name', 'att', 'def', 1]] abspirlist = [['name', 'att', 'def', 1], ['name', 'att', 'def', 1], ['name', 'att', 'def', 1]] You want the number 12, for the total number of nested elements? You can do that with a little fancy work, by generating a list of lengths (in this case: [4, 4, 4]). Then feeding it to the sum function (sum([4,4,4]) evaluates 12). Combining these two ideas gives us: (Toggle Plain Text) sum((len(x) for x in abspirlist)) sum((len(x) for x in abspirlist)) __________________ Waterloo's Canadian Computing Competition (CCC) - Stage 2 Problems, Solutions, and Test Data