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Ka0s · Apr 15th, 2008, 1:18 PM

Well... you are saying that it's not possible to change a string literal declared has a pointer but i've compiled this code and it worked:

#include <stdio.h>

int main() {
	char *a = "hello";
	printf("%s\n", a);
	*a = 'a';
	printf("%s\n", a);

	return 0;
}

When i run the program it shows "hello" followed by "aello".
Can you tell me why can i modify the string pointed by "char *a"?

Apr 15th, 2008, 1:18 PM	#11
Ka0s Newbie Join Date: Apr 2008 Posts: 2 Rep Power: 0	Re: char[] vs char* Well... you are saying that it's not possible to change a string literal declared has a pointer but i've compiled this code and it worked: (Toggle Plain Text) #include <stdio.h> int main() { char a = "hello"; printf("%s\n", a); a = 'a'; printf("%s\n", a); return 0; } #include <stdio.h> int main() { char a = "hello"; printf("%s\n", a); a = 'a'; printf("%s\n", a); return 0; } When i run the program it shows "hello" followed by "aello". Can you tell me why can i modify the string pointed by "char *a"?