View Single Post
Old Mar 26th, 2008, 12:27 AM   #1
mychorhizzae
Newbie
 
Join Date: Mar 2008
Posts: 1
Rep Power: 0 mychorhizzae is on a distinguished road
duplicate numbers in arrays

Hi, I've been lurking here for a while now and decided to make an account to get help. The program I'm trying to write is supposed to:
Read in 20 numbers,
each of which is between 10 and 100, inclusive. As each number is read in, validate
it and store it in the array only if it is not a duplicate of a number already read.
After reading all the values, display only the unique values that the user has
entered.

I have the program functionally working except I don't know what to do for the duplicate cases. Is there an easy way to skip the value entered if duplicate?

#include <iostream>
using namespace std;
#include <iomanip>




int main() {
    int idx = 0;
    int list[20];
    int n;
    int i;
    
    cout << "Enter 20 integers between 10 and 100: " << endl;
    
    for (i=0; i<20; i++){ // user inputs 20 numbers
       
    cin >> n;
    
    if (n < 10 || n > 100){  // input must be between 10 and 100
    cout << "invalid entry" << endl;
}
            list[idx] = n;  //sets each number to the next element in array
              ++idx;

}
    for ( int j = 0; j < 10; j++ )
      cout << list[ j ] << " ";  // print numbers in array
        
    system("pause");
    return 0;
}
mychorhizzae is offline   Reply With Quote