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OpenLoop · Mar 13th, 2008, 6:42 AM

 vb.net Syntax (Toggle Plain Text) 
DIM x AS INTEGER = 4
DIM y AS INTEGER = 0
y = x^3         'x to the power of 3, y = 64
DIM x AS INTEGER = 4
DIM y AS INTEGER = 0
y = x^3         'x to the power of 3, y = 64

Mar 13th, 2008, 6:42 AM	#3
OpenLoop Expert Programmer Join Date: May 2005 Location: East Lansing, MI Posts: 663 Rep Power: 4	Re: problem vb.net Syntax (Toggle Plain Text) DIM x AS INTEGER = 4 DIM y AS INTEGER = 0 y = x^3 'x to the power of 3, y = 64 DIM x AS INTEGER = 4 DIM y AS INTEGER = 0 y = x^3 'x to the power of 3, y = 64