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Sane · Jan 31st, 2008, 3:31 PM

That's pretty intense...

I only assumed it does. I thought create_function returns a reference to the anonymous function, just as a function name is a reference to a named function.

 PHP Syntax (Toggle Plain Text) 
$newfunc = create_function('$a,$b', 'return "ln($a) + ln($b) = " . log($a * $b);');
echo $newfunc(2, M_E);
$newfunc = create_function('$a,$b', 'return "ln($a) + ln($b) = " . log($a * $b);');
echo $newfunc(2, M_E);

Is equivilent to:

 PHP Syntax (Toggle Plain Text) 
function newfunc ($a,$b) { return "ln($a) + ln($b) = " . log($a * $b); }
echo $newfunc(2, M_E);
function newfunc ($a,$b) { return "ln($a) + ln($b) = " . log($a * $b); }
echo $newfunc(2, M_E);

Jan 31st, 2008, 3:31 PM	#11
Sane Programming Guru Join Date: Apr 2005 Location: Waterloo, Ontario Posts: 1,885 Rep Power: 5	Re: Function too convoluted? That's pretty intense... I only assumed it does. I thought create_function returns a reference to the anonymous function, just as a function name is a reference to a named function. PHP Syntax (Toggle Plain Text) $newfunc = create_function('$a,$b', 'return "ln($a) + ln($b) = " . log($a * $b);'); echo $newfunc(2, M_E); $newfunc = create_function('$a,$b', 'return "ln($a) + ln($b) = " . log($a * $b);'); echo $newfunc(2, M_E); Is equivilent to: PHP Syntax (Toggle Plain Text) function newfunc ($a,$b) { return "ln($a) + ln($b) = " . log($a * $b); } echo $newfunc(2, M_E); function newfunc ($a,$b) { return "ln($a) + ln($b) = " . log($a * $b); } echo $newfunc(2, M_E);