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Dec 10th, 2007, 1:52 AM
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#1 |
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Newbie
Join Date: Dec 2007
Location: South Wales
Posts: 6
Rep Power: 0
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Returning Index
Hi all,
I have a bit of a problem with a project and was hoping that somebody could help me out. Here goes! I have a set of integers ie (1,-2,0,4,-5,0,7,-8,0,10) what I need to do is loop through and then return only the positive integers leaving out the negatives. This is easy enough but I have to return the index positions of the positive integers ie, (1,3,4,6,7,9,10). However I'm having major trouble with the logic because I need the integers in reverse order. What I get is the index integers from 1-7 not waht I need. Can anybody help me out with this one. Many thanks in advance. |
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Dec 10th, 2007, 3:07 AM
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#2 |
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Omlette du fromage
Join Date: Oct 2007
Posts: 29
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Re: Returning Index
Just loop the array of integers in reverse.
var integerArray = [1,-2,0,4,-5,0,7,-8,0,10];
var positiveInts = [];
for(var i = integerArray.length - 1, i >= 0, --i)
{
if(integerArray [i] >= 0)
positiveInts[positiveInts.length] = integerArray[i];
} |
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Dec 10th, 2007, 8:39 AM
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#3 |
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Newbie
Join Date: Dec 2007
Location: South Wales
Posts: 6
Rep Power: 0
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Re: Returning Index
Many thanks,
I was getting bogged down by the logic. |
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