Programming Forums - View Single Post

titaniumdecoy · Sep 29th, 2007, 4:53 PM

My point, DaWei, was that the println() method has no effect on how the + operator is treated as the OP suggested in his last post, as this code demonstrates.

(Toggle Plain Text)

Object a = 1 + 13;
Object b = "here:" + 1 + 13;

System.out.println(a);
System.out.println(b);

Sep 29th, 2007, 4:53 PM	#9
titaniumdecoy Expert Programmer Join Date: Nov 2005 Posts: 836 Rep Power: 3	My point, DaWei, was that the println() method has no effect on how the + operator is treated as the OP suggested in his last post, as this code demonstrates. (Toggle Plain Text) Object a = 1 + 13; Object b = "here:" + 1 + 13; System.out.println(a); System.out.println(b); Object a = 1 + 13; Object b = "here:" + 1 + 13; System.out.println(a); System.out.println(b);