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paulchwd · Sep 23rd, 2007, 5:17 PM

Hi All,

I have a label on my aspx page and when I try to set the .Text property of if from the code behind file I get a null reference expeption....

Code behind file for form1

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 catch (MySqlException mysqlx)
            {//<catch>
                showError show = new showError();
                show.printError(mysqlx.Message.ToString(), mysqlx.StackTrace.ToString());
            }//</catch>

Code behind file for form2

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public partial class showError : System.Web.UI.Page
    {
        public void printError(string error, string trace)
        {
            Label2.Text = "xx";
        }
}

Sep 23rd, 2007, 5:17 PM	#1
paulchwd Hobbyist Programmer Join Date: Mar 2005 Posts: 139 Rep Power: 4	Null Reference Expeption... why? Hi All, I have a label on my aspx page and when I try to set the .Text property of if from the code behind file I get a null reference expeption.... Code behind file for form1 (Toggle Plain Text) catch (MySqlException mysqlx) {//<catch> showError show = new showError(); show.printError(mysqlx.Message.ToString(), mysqlx.StackTrace.ToString()); }//</catch> catch (MySqlException mysqlx) {//<catch> showError show = new showError(); show.printError(mysqlx.Message.ToString(), mysqlx.StackTrace.ToString()); }//</catch> Code behind file for form2 (Toggle Plain Text) public partial class showError : System.Web.UI.Page { public void printError(string error, string trace) { Label2.Text = "xx"; } } public partial class showError : System.Web.UI.Page { public void printError(string error, string trace) { Label2.Text = "xx"; } }