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Soulstorm · Sep 2nd, 2007, 5:29 PM

I have a function in which i need to pass as argument an integer array. But how can I know the size of the integer array once this is inside the function?

For example, the following code:

 cpp Syntax (Toggle Plain Text) 
void foo(unsigned *p)
{
	cout << sizeof(p)/4 << '\n';
}
 
int main (int argc, const char * argv[]) {
	unsigned p[] = {1,2,3,4,5,6,7,8,9,0};
	foo(p);
    return 0;
void foo(unsigned *p)
{
	cout << sizeof(p)/4 << '\n';
}

int main (int argc, const char * argv[]) {
	unsigned p[] = {1,2,3,4,5,6,7,8,9,0};
	foo(p);
    return 0;

Will have as a result the number 1. If I try to use the sizeof operator in the main(), it will have the expected results, however, once the pointer of the array is passed as an argument, it seems I cannot use the sizeof operator.

Any ideas?

Sep 2nd, 2007, 5:29 PM	#1
Soulstorm Hobbyist Programmer Join Date: Jan 2006 Location: Menidi, Athens, Greece Posts: 243 Rep Power: 3	Passing int arrays as arguments... I have a function in which i need to pass as argument an integer array. But how can I know the size of the integer array once this is inside the function? For example, the following code: cpp Syntax (Toggle Plain Text) void foo(unsigned p) { cout << sizeof(p)/4 << '\n'; } int main (int argc, const char argv[]) { unsigned p[] = {1,2,3,4,5,6,7,8,9,0}; foo(p); return 0; void foo(unsigned p) { cout << sizeof(p)/4 << '\n'; } int main (int argc, const char argv[]) { unsigned p[] = {1,2,3,4,5,6,7,8,9,0}; foo(p); return 0; Will have as a result the number 1. If I try to use the sizeof operator in the main(), it will have the expected results, however, once the pointer of the array is passed as an argument, it seems I cannot use the sizeof operator. Any ideas? __________________ Project::Soulstorm (personal homepage)