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357mag · Jul 27th, 2007, 10:08 PM

So let me get this straight. The first time through the loop the compiler is doing this:

0111 1011
1000 0000
----------
0000 0000    // Java interprets the whole thing as false since there is no 1's 
                  // present in any of the bit positions

Likewise the second time through the loop it does this:

(Toggle Plain Text)

0111 1011
0100 0000
----------
0100 0000    // Java interprets this as being true because there is a 1 bit
                  // present

So the compiler looks and does the math for all 8 columns, and if the end result shows a 1 in any of the bit positions, the if statement is true causing the compiler to print a 1.

So the compiler really does see and do the math for all the bit positions, not just one column at a time.

Jul 27th, 2007, 10:08 PM	#10
357mag Hobbyist Programmer Join Date: Mar 2005 Posts: 148 Rep Power: 4	So let me get this straight. The first time through the loop the compiler is doing this: (Toggle Plain Text) 0111 1011 1000 0000 ---------- 0000 0000 // Java interprets the whole thing as false since there is no 1's // present in any of the bit positions 0111 1011 1000 0000 ---------- 0000 0000 // Java interprets the whole thing as false since there is no 1's // present in any of the bit positions Likewise the second time through the loop it does this: (Toggle Plain Text) 0111 1011 0100 0000 ---------- 0100 0000 // Java interprets this as being true because there is a 1 bit // present 0111 1011 0100 0000 ---------- 0100 0000 // Java interprets this as being true because there is a 1 bit // present So the compiler looks and does the math for all 8 columns, and if the end result shows a 1 in any of the bit positions, the if statement is true causing the compiler to print a 1. So the compiler really does see and do the math for all the bit positions, not just one column at a time.