Programming Forums - View Single Post

357mag · Jul 6th, 2007, 10:52 PM

I adjusted the numbers a bit:

print '%3d  %7d' % (i, square(i))

The numbers 3 and 7 that follow the percentage sign I believe mean to tell the compiler to right justify the number in a field width of 3 character postions, and the next number would be right justified in a field width of 7 character positions. But when I count the number of character positions from the first number to where the second number(under the Square column)is located, no way is that just 7. It's gotta be more than that.

Jul 6th, 2007, 10:52 PM	#4
357mag Hobbyist Programmer Join Date: Mar 2005 Posts: 148 Rep Power: 4	I adjusted the numbers a bit: (Toggle Plain Text) print '%3d %7d' % (i, square(i)) print '%3d %7d' % (i, square(i)) The numbers 3 and 7 that follow the percentage sign I believe mean to tell the compiler to right justify the number in a field width of 3 character postions, and the next number would be right justified in a field width of 7 character positions. But when I count the number of character positions from the first number to where the second number(under the Square column)is located, no way is that just 7. It's gotta be more than that.