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Silicon_Pudding · Mar 15th, 2007, 1:41 AM

ITERATE=240
for COUNT in `seq -w 1 $TOTAL`
do
  OTHER=$(($COUNT*2))
  ... more stuff
  ...
done

The problem I am having is that I can't figure out how to multiply COUNT by 2. In this example since TOTAL is 240, COUNT will be 3 digits. I get an error message at count 8 saying the value is too great for the base, which I assume is because of 3 digits and something with binary.

Is there a way I can multiply this number by two, while still interating through by one?

Mar 15th, 2007, 1:41 AM	#1
Silicon_Pudding Newbie Join Date: Jun 2006 Location: In a box Posts: 27 Rep Power: 0	Help with this code (Toggle Plain Text) ITERATE=240 for COUNT in `seq -w 1 $TOTAL` do OTHER=$(($COUNT2)) ... more stuff ... done ITERATE=240 for COUNT in `seq -w 1 $TOTAL` do OTHER=$(($COUNT2)) ... more stuff ... done The problem I am having is that I can't figure out how to multiply COUNT by 2. In this example since TOTAL is 240, COUNT will be 3 digits. I get an error message at count 8 saying the value is too great for the base, which I assume is because of 3 digits and something with binary. Is there a way I can multiply this number by two, while still interating through by one? __________________ ~ Silicon Enhanced Pudding "It's magically delicious"