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Serinth · Feb 21st, 2007, 2:59 PM

So let me get this straight, you want to call b.bash from a.bash but it's giving you an error in path. I think the problem is that you used ./path/b.bash. I believe you can exclude the .

Feb 21st, 2007, 2:59 PM	#2
Serinth Programmer Join Date: Sep 2005 Posts: 50 Rep Power: 3	So let me get this straight, you want to call b.bash from a.bash but it's giving you an error in path. I think the problem is that you used ./path/b.bash. I believe you can exclude the . __________________ A girl talked to me once. http://www.latestanime.com