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Thiengineer · Feb 4th, 2007, 6:41 PM

I need help with the following problem about swapping pointers.

The following code is in main:

	main()
        {
           int x=1,y=2;
           int *xp,*yp;
           .
           .
           .
           xp = &x;
           yp = &y;
           intpswap(<arg1>,<arg2>);
           x=3;y=4;
           printf("*xp = %d, *yp = %d\n",*xp,*yp); 
        }

Write a function called intpswap that swaps what xp and yp point at,
and thus printf prints "*xp = 4, *yp =3".

I know how to swap int values by using a temp variable, but is it the same approach here?

Any help or hints will be greatly appreciated!!

Thank you!!

Feb 4th, 2007, 6:41 PM	#1
Thiengineer Newbie Join Date: Feb 2007 Posts: 2 Rep Power: 0	How do I swap pointers with a function? I need help with the following problem about swapping pointers. The following code is in main: (Toggle Plain Text) main() { int x=1,y=2; int xp,yp; . . . xp = &x; yp = &y; intpswap(<arg1>,<arg2>); x=3;y=4; printf("xp = %d, yp = %d\n",xp,yp); } main() { int x=1,y=2; int xp,yp; . . . xp = &x; yp = &y; intpswap(<arg1>,<arg2>); x=3;y=4; printf("xp = %d, yp = %d\n",xp,yp); } Write a function called intpswap that swaps what xp and yp point at, and thus printf prints "xp = 4, yp =3". I know how to swap int values by using a temp variable, but is it the same approach here? Any help or hints will be greatly appreciated!! Thank you!! Last edited by Thiengineer; Feb 4th, 2007 at 7:09 PM.