Eric the Red

Your solution Arevos worked ... and for that I would like to give you a kiss. However, since I'm not gay I will just say thank you and have a nice day.

Also thank you everyone else who has put time into this.

__________________
Death smiles at us all. All a man can do is smile back.

titaniumdecoy

I would be more than happy if someone could explain to me why that code compiles under Java 5. According to Sun's documentation, the following is the correct way to call printf:

Arevos

You're welcome. It's nice to know that a year spent working with Eclipse still has it's uses

Both ways work. Java 5 also introduced varargs, which are denoted by an ellipses (...) after the type. If you look at the type of the function:
You'll notice that the end argument isn't a normal array. IIRC, you can use it in one of two ways. Like this:
Or like this:
The two are equivalent; the second form is essentially just syntactic sugar for the first. Incidentally, C# has exactly the same functionality, which behaves in exactly the same way, but uses the keyword "params" instead.

Also, this type of string creation:
Is almost always wrong and bad. The only time it's of possible use is when dealing with small substrings of large strings. I can go into detail, if anyone's really interested in the strange little nooks and crannies of Java.

titaniumdecoy

Thanks for the explanation, Arevos. I had never heard of varargs before (in Java, that is).