Programming Forums - View Single Post - Retaining the contents of a list during a recursive function

nytrokiss · Nov 16th, 2006, 11:31 PM

def find_all_items(site):
    site = urllib.urlopen(site).read()
    all_items = re.findall(r'watch\.asp\?\w+\=\w*\&\w*\=\w+',site)
    next_page = re.findall(r'Watches\.asp\?\w+\=[0-9]+\&pg\=\w+',site)
    try:
        find_all_items(urllib.basejoin("<some url>",next_page[0]))
    except IndexError:
        pass
    return remove_dups(all_items) # ,<---- this removes all the duplicate items

How do i keep the value of all_items that i have within the first function call and return a list of all the items at once also from the second function call

Now the list is being overwritten

Nov 16th, 2006, 11:31 PM	#1
nytrokiss Newbie Join Date: Oct 2006 Posts: 23 Rep Power: 0	Retaining the contents of a list during a recursive function (Toggle Plain Text) def find_all_items(site): site = urllib.urlopen(site).read() all_items = re.findall(r'watch\.asp\?\w+\=\w\&\w\=\w+',site) next_page = re.findall(r'Watches\.asp\?\w+\=[0-9]+\&pg\=\w+',site) try: find_all_items(urllib.basejoin("<some url>",next_page[0])) except IndexError: pass return remove_dups(all_items) # ,<---- this removes all the duplicate items def find_all_items(site): site = urllib.urlopen(site).read() all_items = re.findall(r'watch\.asp\?\w+\=\w\&\w\=\w+',site) next_page = re.findall(r'Watches\.asp\?\w+\=[0-9]+\&pg\=\w+',site) try: find_all_items(urllib.basejoin("<some url>",next_page[0])) except IndexError: pass return remove_dups(all_items) # ,<---- this removes all the duplicate items How do i keep the value of all_items that i have within the first function call and return a list of all the items at once also from the second function call Now the list is being overwritten