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Ghosty · Nov 7th, 2006, 10:38 PM

Please examine the following code:

#include <iostream>
#include <stdlib.h>

using namespace std;

int main(){

  char * envVar;
  envVar = getenv ("PS1");

  cout << "PS1 value is currently: " << *envVar << endl;
  cout << "We will now use putenv to change the PS1 variable" << endl;

  putenv("PS1=<duck>");

  envVar = getenv ("PS1");
  cout << "PS1 value is currently: " << *envVar << endl;
  return 0;
}

My book says that I have to use malloc aquire more space for "<duck>" but I've never used the malloc function. Can anyone tell me how to use malloc or now to use, perhaps, the new call?

Nov 7th, 2006, 10:38 PM	#1
Ghosty Newbie Join Date: May 2005 Location: NJ Posts: 18 Rep Power: 0	setting env vars in unix Please examine the following code: (Toggle Plain Text) #include <iostream> #include <stdlib.h> using namespace std; int main(){ char * envVar; envVar = getenv ("PS1"); cout << "PS1 value is currently: " << envVar << endl; cout << "We will now use putenv to change the PS1 variable" << endl; putenv("PS1=<duck>"); envVar = getenv ("PS1"); cout << "PS1 value is currently: " << envVar << endl; return 0; } #include <iostream> #include <stdlib.h> using namespace std; int main(){ char * envVar; envVar = getenv ("PS1"); cout << "PS1 value is currently: " << envVar << endl; cout << "We will now use putenv to change the PS1 variable" << endl; putenv("PS1=<duck>"); envVar = getenv ("PS1"); cout << "PS1 value is currently: " << envVar << endl; return 0; } My book says that I have to use malloc aquire more space for "<duck>" but I've never used the malloc function. Can anyone tell me how to use malloc or now to use, perhaps, the new call?