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lostcauz · Nov 29th, 2004, 1:59 AM

I've had a few cocktails but I'll do my best. Using a div instruction, load (e)ax with the number being tested then load cx with the divisor. Then use the instruction - div cx. The quotient will be in ax while the remainder, if any, will be left in dx.

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mov cx, 3
mov ax, 31
div cx

You could try this code in debug and watch the registers to see whats going on.
At command line type 'debug'
type 'a'
enter the code above
when done click enter twice then type 'r'
type 't' to execute the next instruction and see the registers change.
In the end ax should be 10 while dx contains the remainder of 1.
Forgive if this makes no sense.

Nov 29th, 2004, 1:59 AM	#4
lostcauz Hobbyist Programmer Join Date: Nov 2004 Location: 1691 miles East of L.A. Posts: 159 Rep Power: 4	I've had a few cocktails but I'll do my best. Using a div instruction, load (e)ax with the number being tested then load cx with the divisor. Then use the instruction - div cx. The quotient will be in ax while the remainder, if any, will be left in dx. (Toggle Plain Text) mov cx, 3 mov ax, 31 div cx mov cx, 3 mov ax, 31 div cx You could try this code in debug and watch the registers to see whats going on. At command line type 'debug' type 'a' enter the code above when done click enter twice then type 'r' type 't' to execute the next instruction and see the registers change. In the end ax should be 10 while dx contains the remainder of 1. Forgive if this makes no sense. __________________ -- lostcauz Stepped in what?... Behind whose barn?... I didn't even know they had a cow!