Programming Forums > Application Development > C++

n00b · Nov 6th, 2006, 11:57 AM

if i write the code like...

int number;
	cout << "Enter a number: "; cin >> number;
	while(!cin)
	{
		cin.clear();
		cin.ignore(100,'\n');
		cout << "Enter a NUMBER: " << endl;
		cin >> number;
	};

...to make sure the user inputs digits only, it works fine. but if i have a variable of "char" type, it wont wont print the warning if i enter digits instead of characters. how do i solve this?

Narue · Nov 6th, 2006, 12:51 PM

>but if i have a variable of "char" type, it wont wont print the warning if i enter digits instead of characters.
That's because all user input is character based. Even if you type a digit, it's still the character representation of that digit.

>how do i solve this?
You have to manually validate each character using one of the functions in <cctype> or read everything as a string and parse using one of several common methods.

n00b · Nov 6th, 2006, 2:52 PM

rgr that, the last solution will do

Nov 6th, 2006, 11:57 AM	#1
n00b Programmer Join Date: Sep 2005 Posts: 69 Rep Power: 4	input control if i write the code like... (Toggle Plain Text) int number; cout << "Enter a number: "; cin >> number; while(!cin) { cin.clear(); cin.ignore(100,'\n'); cout << "Enter a NUMBER: " << endl; cin >> number; }; int number; cout << "Enter a number: "; cin >> number; while(!cin) { cin.clear(); cin.ignore(100,'\n'); cout << "Enter a NUMBER: " << endl; cin >> number; }; ...to make sure the user inputs digits only, it works fine. but if i have a variable of "char" type, it wont wont print the warning if i enter digits instead of characters. how do i solve this?

Nov 6th, 2006, 12:51 PM	#2
Narue Professional Programmer Join Date: Sep 2005 Posts: 419 Rep Power: 4	>but if i have a variable of "char" type, it wont wont print the warning if i enter digits instead of characters. That's because all user input is character based. Even if you type a digit, it's still the character representation of that digit. >how do i solve this? You have to manually validate each character using one of the functions in <cctype> or read everything as a string and parse using one of several common methods. __________________ Even if the voices aren't real, they have some pretty good ideas.

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Nov 6th, 2006, 2:52 PM	#3
n00b Programmer Join Date: Sep 2005 Posts: 69 Rep Power: 4	rgr that, the last solution will do

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Programming Forums > Application Development > C++

input control