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magnus.therning · Oct 24th, 2006, 4:29 AM

You need some parentheses around the list pattern:

getelem 0 (x:xs) = x
getelem n (x:xs) = getelem (n - 1) xs

By terminating on 0 you have made the function count elements from 0, rather than from 1 (as was suggested in the original post). I think starting from 0 is a better choice though :-)

Oct 24th, 2006, 4:29 AM	#3
magnus.therning Programmer Join Date: May 2006 Location: Cambridge, UK Posts: 36 Rep Power: 0	You need some parentheses around the list pattern: (Toggle Plain Text) getelem 0 (x:xs) = x getelem n (x:xs) = getelem (n - 1) xs getelem 0 (x:xs) = x getelem n (x:xs) = getelem (n - 1) xs By terminating on 0 you have made the function count elements from 0, rather than from 1 (as was suggested in the original post). I think starting from 0 is a better choice though :-) __________________ Don't comment bad code - rewrite it. - The Elements of Programming Style (Kernighan & Plaugher)