Programming Forums > Script Programming > Bash / Shell Scripting

a thing · Aug 17th, 2006, 12:36 AM

I was looking back through the threads I started and came across http://programmingforums.org/forum/s...38&postcount=6. I thought that would be more accurate, so I've been trying to construct a function that prints the fastest domain from the list of domains given to it. So far I have:

(Toggle Plain Text)

#!/bin/sh

getmirror()
{
	declare -a averages #Make sure $averages doesn't get thrown away too soon by garbage collection.
	i=0
	for mirror; do
		averages[i]="$(ping -c 2 $mirror|tail -n1|cut -d/ -f5|cut -d. -f1)"
		i=$(expr $i + 1)
	done
	IFS="
" #So sort will count different elements of $averages as different values.
	bestaverage=$(echo "${averages[*]}"|sort -n|head -n1)
	size="${#averages[*]}"
	echo $bestaverage
	for (( i=0; "${averages[i]}" != "$bestaverage"; i++ )); do echo; done #The shell complains if there's nothing between do and ;done.
	echo $i
}

echo $(getmirror jaist.dl.sourceforge.net switch.dl.sourceforge.net easynews.dl.sourceforge.net)

My problems:
1. How would I reference the argument number $i? So if $i == 2, then reference $2. Like $$i, but that's not the correct syntax.
2. What's the best way to round a number? [ complains if there are decimals passed to it. cut -d. -f1 sort of works, but it isn't the most accurate.

Aug 17th, 2006, 12:36 AM	#1
a thing Unverified User Join Date: Aug 2005 Location: none Posts: 146 Rep Power: 0	$$i and rounding I was looking back through the threads I started and came across http://programmingforums.org/forum/s...38&postcount=6. I thought that would be more accurate, so I've been trying to construct a function that prints the fastest domain from the list of domains given to it. So far I have: (Toggle Plain Text) #!/bin/sh getmirror() { declare -a averages #Make sure $averages doesn't get thrown away too soon by garbage collection. i=0 for mirror; do averages[i]="$(ping -c 2 $mirror\|tail -n1\|cut -d/ -f5\|cut -d. -f1)" i=$(expr $i + 1) done IFS=" " #So sort will count different elements of $averages as different values. bestaverage=$(echo "${averages[]}"\|sort -n\|head -n1) size="${#averages[]}" echo $bestaverage for (( i=0; "${averages[i]}" != "$bestaverage"; i++ )); do echo; done #The shell complains if there's nothing between do and ;done. echo $i } echo $(getmirror jaist.dl.sourceforge.net switch.dl.sourceforge.net easynews.dl.sourceforge.net) #!/bin/sh getmirror() { declare -a averages #Make sure $averages doesn't get thrown away too soon by garbage collection. i=0 for mirror; do averages[i]="$(ping -c 2 $mirror\|tail -n1\|cut -d/ -f5\|cut -d. -f1)" i=$(expr $i + 1) done IFS=" " #So sort will count different elements of $averages as different values. bestaverage=$(echo "${averages[]}"\|sort -n\|head -n1) size="${#averages[]}" echo $bestaverage for (( i=0; "${averages[i]}" != "$bestaverage"; i++ )); do echo; done #The shell complains if there's nothing between do and ;done. echo $i } echo $(getmirror jaist.dl.sourceforge.net switch.dl.sourceforge.net easynews.dl.sourceforge.net) My problems: 1. How would I reference the argument number $i? So if $i == 2, then reference $2. Like $$i, but that's not the correct syntax. 2. What's the best way to round a number? [ complains if there are decimals passed to it. cut -d. -f1 sort of works, but it isn't the most accurate. __________________ Warning: My posts may change (dramatically) within the first 15 minutes they're posted. Got 'Nux?�GNU/Linux and other free software support. It's GNU/Linux, not just Linux. Last edited by a thing; Aug 17th, 2006 at 12:50 AM.

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Programming Forums > Script Programming > Bash / Shell Scripting

$$i and rounding