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#1 |
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Programmer
Join Date: Jan 2008
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How to skip a number in java
Hello to all.
I have this code for my class and I what I am trying to do is decrement the number 39 by two so that odd numbers show, until I get to zero using the "for loop" The issue is that I am suppose to exclude the numbers 33, and 3 when it prints the numbers out. I can't figure that part out, and I can't find it anywhere in the chapter that I had to read on this. Can someone please help me understand how i should do this? This is the code I have so far, but I took out the extra for statements for clarity, beacuse I thought they would help me but they don't. If I am suppose to use if statements, I don't know how to do this excluding 3 and 33. Java Syntax (Toggle Plain Text)
Last edited by big_k105; Apr 10th, 2008 at 7:43 PM. |
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#2 |
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Programmer
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Re: How to skip a number in java
Hey everyone, I figured it out about 5 minutes after I asked. Sorry, but thanks to those who would have helped anyway.
Here is the solution that I found worked. Java Syntax (Toggle Plain Text)
Last edited by big_k105; Apr 10th, 2008 at 7:44 PM. |
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#3 | |
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I eat cake for breakfast.
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Re: How to skip a number in java
There's a simpler way to do it, using an
if statement. Here's the pseudocode:loop i from 39 to 0 step 2:
if i != 33 and i != 3:
print i + " "
end if
end loopBy the way, to enclose Java code, you should do this: Quote:
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#4 |
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Hobbyist Programmer
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Re: How to skip a number in java
did you mean "every time the digit 3 is attained, ignore it"? or just the values 33 & 3? If its any digit, 3, then you might want to use some kind of toString() then get rid of the 3 then toInt()
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