Programming Forums > Application Development > C

takumi8374 · May 23rd, 2005, 7:49 PM

Hi, I dont really know how to write the function to compute the final score, which is equal to 0.75(quiz1+quiz2+quiz3)+0.25(exam1+exam2+exam3).

(Toggle Plain Text)

#include<stdio.h>

#define NAME 25
#define SOCIAL 12
#define PHONE 15
#define QUIZ 13
#define EXAM 13
#define FINAL 3
#define SIZE 2

struct {
	char first[NAME];
	char last[NAME];
}typedef Name;

struct {
	int first3;
	int middle2;
	int last4;
}typedef Social;

struct {
	int code;
	int first3;
	int last4;
}typedef Phone;

struct {
	int quiz1[QUIZ];
	int quiz2[QUIZ];
	int quiz3[QUIZ];
}typedef Quiz;

struct {
	int exam1;
	int exam2;
	int exam3;
}typedef Exam;

struct {
	Name name;
	Social social;
	Phone phone;
	Quiz quiz;
	Exam exam;
} typedef Grade;

void enterGrade(Grade *cptr);

int Final(int quiz int exam);

int main()
{
	Grade grade[SIZE];
	int x;
	
	for(x=0;x<SIZE;x++);
		enterGrade(&grade);

	return 0;
}

void enterGrade(Grade *cptr)
{
	
	printf("Enter first name: ");
	gets(cptr->name.first);
	printf("Enter last name: ");
	gets(cptr->name.last);
	printf("Enter social sercurity number: ");
	scanf("%s", &cptr->social.first3, &cptr->social.middle2,
		  &cptr->social.last4);
	printf("Enter phone number: ");
	scanf("%s", &cptr->phone.code,&cptr->phone.first3,&cptr->phone.last4);
	printf("Enter 1st quiz score: ");
	scanf("%d", &cptr->quiz.quiz1);
	printf("Enter 2nd quiz score: ");
	scanf("%d", &cptr->quiz.quiz2);
	printf("Enter 3rd quiz score: ");
	scanf("%d", &cptr->quiz.quiz3);
	printf("Enter 1st exam score: ");
	scanf("%d", &cptr->exam.exam1);
	printf("Enter 2nd exam score: ");
	scanf("%d", &cptr->exam.exam2);
	printf("Enter 3rd exam score: ");
	scanf("%d", &cptr->exam.exam3);


}

int Final (int quiz int exam)
{
	Final = 0.75(&cptr->quiz.quiz1+&cptr->quiz.quiz2+&cptr->quiz.quiz3)+
			0.25(&cptr->exam.exam1+&cptr->exam.exam2+&cptr->exam.exam3);
	return x;
}

Jessehk · May 26th, 2005, 10:09 PM

I didn't read the code, just what you wanted to do.

declare (A.K.A: create )(if there isn't one already) a variable called int total

then add this line where you want to calculate the total

(Toggle Plain Text)

total = 0.75(quiz1+quiz2+quiz3)+0.25(exam1+exam2+exam3);

display the variable as you wish

eg:

(Toggle Plain Text)

printf(Your Total score is %s.\n", total);

I don't know if that is what you wanted, but I tried.

Ooble · May 27th, 2005, 4:49 AM

You want a couple of *s in there:

(Toggle Plain Text)

total = 0.75 * (quiz1 + quiz2 + quiz3) + 0.25 * (exam1 + exam2 + exam3);

DaWei · Jun 3rd, 2005, 9:04 AM

Ooble solved your immediate problem. I looked at your code and you are courting plenty more. "Gets" is not a good function to use -- it is susceptible to the dreaded buffer overflow that one hears so much about. Many other mechanisms can be misused, also, but there is just about NO way to do other than misuse "gets". Also, you may not have noticed when you looked up the function, but "scanf" provides a return. To ignore it is to expect the customers, clients, and users to pamper you like yo mama would. Anottagonnahappen in the real world.

mitakeet · Jun 3rd, 2005, 9:14 AM

Hey DaWei, glad to see you! I guess we need to rebuild our sticky from DevShed, eh?

Spectre5 · Jun 3rd, 2005, 11:50 AM

Ya...nice to see all the DevSheders showing up here

May 23rd, 2005, 7:49 PM	#1
takumi8374 Newbie Join Date: May 2005 Posts: 6 Rep Power: 0	Help Plz Hi, I dont really know how to write the function to compute the final score, which is equal to 0.75(quiz1+quiz2+quiz3)+0.25(exam1+exam2+exam3). (Toggle Plain Text) #include<stdio.h> #define NAME 25 #define SOCIAL 12 #define PHONE 15 #define QUIZ 13 #define EXAM 13 #define FINAL 3 #define SIZE 2 struct { char first[NAME]; char last[NAME]; }typedef Name; struct { int first3; int middle2; int last4; }typedef Social; struct { int code; int first3; int last4; }typedef Phone; struct { int quiz1[QUIZ]; int quiz2[QUIZ]; int quiz3[QUIZ]; }typedef Quiz; struct { int exam1; int exam2; int exam3; }typedef Exam; struct { Name name; Social social; Phone phone; Quiz quiz; Exam exam; } typedef Grade; void enterGrade(Grade cptr); int Final(int quiz int exam); int main() { Grade grade[SIZE]; int x; for(x=0;x<SIZE;x++); enterGrade(&grade); return 0; } void enterGrade(Grade cptr) { printf("Enter first name: "); gets(cptr->name.first); printf("Enter last name: "); gets(cptr->name.last); printf("Enter social sercurity number: "); scanf("%s", &cptr->social.first3, &cptr->social.middle2, &cptr->social.last4); printf("Enter phone number: "); scanf("%s", &cptr->phone.code,&cptr->phone.first3,&cptr->phone.last4); printf("Enter 1st quiz score: "); scanf("%d", &cptr->quiz.quiz1); printf("Enter 2nd quiz score: "); scanf("%d", &cptr->quiz.quiz2); printf("Enter 3rd quiz score: "); scanf("%d", &cptr->quiz.quiz3); printf("Enter 1st exam score: "); scanf("%d", &cptr->exam.exam1); printf("Enter 2nd exam score: "); scanf("%d", &cptr->exam.exam2); printf("Enter 3rd exam score: "); scanf("%d", &cptr->exam.exam3); } int Final (int quiz int exam) { Final = 0.75(&cptr->quiz.quiz1+&cptr->quiz.quiz2+&cptr->quiz.quiz3)+ 0.25(&cptr->exam.exam1+&cptr->exam.exam2+&cptr->exam.exam3); return x; } #include<stdio.h> #define NAME 25 #define SOCIAL 12 #define PHONE 15 #define QUIZ 13 #define EXAM 13 #define FINAL 3 #define SIZE 2 struct { char first[NAME]; char last[NAME]; }typedef Name; struct { int first3; int middle2; int last4; }typedef Social; struct { int code; int first3; int last4; }typedef Phone; struct { int quiz1[QUIZ]; int quiz2[QUIZ]; int quiz3[QUIZ]; }typedef Quiz; struct { int exam1; int exam2; int exam3; }typedef Exam; struct { Name name; Social social; Phone phone; Quiz quiz; Exam exam; } typedef Grade; void enterGrade(Grade cptr); int Final(int quiz int exam); int main() { Grade grade[SIZE]; int x; for(x=0;x<SIZE;x++); enterGrade(&grade); return 0; } void enterGrade(Grade cptr) { printf("Enter first name: "); gets(cptr->name.first); printf("Enter last name: "); gets(cptr->name.last); printf("Enter social sercurity number: "); scanf("%s", &cptr->social.first3, &cptr->social.middle2, &cptr->social.last4); printf("Enter phone number: "); scanf("%s", &cptr->phone.code,&cptr->phone.first3,&cptr->phone.last4); printf("Enter 1st quiz score: "); scanf("%d", &cptr->quiz.quiz1); printf("Enter 2nd quiz score: "); scanf("%d", &cptr->quiz.quiz2); printf("Enter 3rd quiz score: "); scanf("%d", &cptr->quiz.quiz3); printf("Enter 1st exam score: "); scanf("%d", &cptr->exam.exam1); printf("Enter 2nd exam score: "); scanf("%d", &cptr->exam.exam2); printf("Enter 3rd exam score: "); scanf("%d", &cptr->exam.exam3); } int Final (int quiz int exam) { Final = 0.75(&cptr->quiz.quiz1+&cptr->quiz.quiz2+&cptr->quiz.quiz3)+ 0.25(&cptr->exam.exam1+&cptr->exam.exam2+&cptr->exam.exam3); return x; } Last edited by takumi8374; May 23rd, 2005 at 8:03 PM.

May 26th, 2005, 10:09 PM	#2
Jessehk The Oblivious One Join Date: May 2005 Location: Ontario, Canada Posts: 644 Rep Power: 4	I didn't read the code, just what you wanted to do. declare (A.K.A: create )(if there isn't one already) a variable called int total then add this line where you want to calculate the total (Toggle Plain Text) total = 0.75(quiz1+quiz2+quiz3)+0.25(exam1+exam2+exam3); total = 0.75(quiz1+quiz2+quiz3)+0.25(exam1+exam2+exam3); display the variable as you wish eg: (Toggle Plain Text) printf(Your Total score is %s.\n", total); printf(Your Total score is %s.\n", total); I don't know if that is what you wanted, but I tried. Last edited by Jessehk; May 26th, 2005 at 10:19 PM.

May 27th, 2005, 4:49 AM	#3
Ooble I eat cake for breakfast. Join Date: Jul 2004 Location: In my box. Posts: 4,434 Rep Power: 9	You want a couple of s in there: (Toggle Plain Text) total = 0.75 (quiz1 + quiz2 + quiz3) + 0.25 * (exam1 + exam2 + exam3); total = 0.75 * (quiz1 + quiz2 + quiz3) + 0.25 * (exam1 + exam2 + exam3); __________________ Me :: You :: Them

Jun 3rd, 2005, 9:04 AM	#4
DaWei Resident Grouch Join Date: Jun 2005 Posts: 6,453 Rep Power: 10	Ooble solved your immediate problem. I looked at your code and you are courting plenty more. "Gets" is not a good function to use -- it is susceptible to the dreaded buffer overflow that one hears so much about. Many other mechanisms can be misused, also, but there is just about NO way to do other than misuse "gets". Also, you may not have noticed when you looked up the function, but "scanf" provides a return. To ignore it is to expect the customers, clients, and users to pamper you like yo mama would. Anottagonnahappen in the real world. __________________ Abstraction doesn't make it impossible to write bad code; it makes it possible to write superior code. Contributor's Corner: Grumpy on C++ Exceptions DaWei on Pointers

Jun 3rd, 2005, 9:14 AM	#5
mitakeet Programmer Join Date: Jun 2005 Location: Maryland, USA Posts: 59 Rep Power: 4	Hey DaWei, glad to see you! I guess we need to rebuild our sticky from DevShed, eh? __________________ Free code: http://sol-biotech.com/code/. It is not that old programmers are any smarter or code better, it is just that they have made the same stupid mistake so many times that it is second nature to fix it. --Mitakeet The reasonable man adapts himself to the world; the unreasonable one persists in trying to adapt the world to himself. Therefore, all progress depends on the unreasonable man. --George Bernard Shaw

Jun 3rd, 2005, 11:50 AM	#6
Spectre5 Newbie Join Date: Jun 2005 Posts: 8 Rep Power: 0	Ya...nice to see all the DevSheders showing up here

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Programming Forums > Application Development > C

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