Programming Forums > Script Programming > Python

Fred · Feb 26th, 2005, 4:23 PM

What is wrong with this code?

Source = raw_input("File's path: C:/")
If Source[0:3] == 'C:/':
    print 'Invalid path'

This is actually just thought to take the path of a file, and then make sure, that 'C:/' is not entered twice.
When I try to run it though, I am getting an error message at the variable 'Source', which is marked as invalid syntax. Why???

thanx

al1986 · Feb 26th, 2005, 7:24 PM

Simple mistake - it looks like you've used a capital "I" in the if statement.

Feb 26th, 2005, 4:23 PM	#1
Fred Programmer Join Date: Feb 2005 Posts: 67 Rep Power: 4	What is wrong with the following code? What is wrong with this code? (Toggle Plain Text) Source = raw_input("File's path: C:/") If Source[0:3] == 'C:/': print 'Invalid path' Source = raw_input("File's path: C:/") If Source[0:3] == 'C:/': print 'Invalid path' This is actually just thought to take the path of a file, and then make sure, that 'C:/' is not entered twice. When I try to run it though, I am getting an error message at the variable 'Source', which is marked as invalid syntax. Why??? thanx

Thread Tools
Show Printable Version Email this Page
Display Modes
Linear Mode Switch to Hybrid Mode Switch to Threaded Mode

Feb 26th, 2005, 7:24 PM	#2
al1986 Newbie Join Date: Feb 2005 Posts: 24 Rep Power: 0	Simple mistake - it looks like you've used a capital "I" in the if statement.

Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)

Programming Forums > Script Programming > Python

What is wrong with the following code?