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Dec 20th, 2006, 12:20 PM
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#1 |
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Rusty -- explain byte order.
jmp 0xf000:0xff00
Because I've not touched Assembly since school (12+ years ago), I cannot remember what this does. What I think this does is "Jump to the offset address at 0x000fff00", however, I cannot remember how the byte order goes. Thanks in advance for your explination. |
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Dec 20th, 2006, 3:57 PM
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#2 |
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That's segmented addressing. Multiply the segment part by 16 (add a 0 on the end) and add it to the address part. That would result in 0fff00. This kind of addressing is exactly why Intel was considered a piece of shit by system pros. Good thing they were chosen by IBM. It saved their ass.
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Dec 20th, 2006, 4:08 PM
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#3 |
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I had to work it out on paper to figure out what you were talking about. . . but I got it. Thanks!
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