Programming Forums > Application Development > Java

Jakeyman_I_Am · Jun 13th, 2006, 7:43 PM

Hello! I have a issue here, and to be honest I have seen this beofre, but I cannot remember how I corrected it. The problem is in this line:

Names[custNum] = input.nextLine();

the problem is that it skips that line.. completely. That is the second input line in the constructor, and is followed by a system.out.println(); line. if you need more ask! Thanks!

Booooze · Jun 13th, 2006, 7:55 PM

(Toggle Plain Text)

the problem is that it skips that line

Obviously, that line isn't excuting to skip itself. Post more of the code.

Jakeyman_I_Am · Jun 13th, 2006, 8:02 PM

Quote:

Originally Posted by Booooze

(Toggle Plain Text)

the problem is that it skips that line

Obviously, that line isn't excuting to skip itself. Post more of the code.

public static void saveBalance()
{
System.out.println("-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*");

System.out.print("Please tell me, what is the ID of the customer?");
custNum = input.nextInt();

System.out.println("Thank you!");
System.out.print("Now please tell me this customer's name?(" + custNum + "):");
Names[custNum] = input.nextLine();

System.out.println(" ");

System.out.println("Thank You!");
System.out.print("Now please tell me " + Names[custNum] + "'s balance: ");
Balance[custNum] = input.nextDouble();

System.out.println("-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*");

control();
}

Jakeyman_I_Am · Jun 13th, 2006, 8:03 PM

Also, further down in the program, the code skips the very same type line. (A input.nextLine) And I do remeber this is class being a topic my teacher covered. I just don't remember what he said..

DaWei · Jun 13th, 2006, 8:09 PM

Read the forum's rules/FAQ. You can learn about code tags there, and discover other things regarding the community which you wish to use as a resource. It's only the neighborly thing to do.

Booooze · Jun 13th, 2006, 8:11 PM

Ok, first off a couple things:

#1 - put your code in code tags if you want anyone to help. (honestly)
#2- I'm looking at this page: http://www.cs.wisc.edu/~cs302/io/JavaIO_Scanner.html
Are you sure your defining custNum properly? I think when you get the user input, its going to be a string. You will need to convert it. Also where is it defined? Im not big on Java, but hope this helped. Last thing, are you getting any errors when you execute the code?

Jakeyman_I_Am · Jun 13th, 2006, 8:19 PM

I am sorry. I come from a forum with no such rules. Anyways here is the code again, and I put a comment in where it skipps. Also, if I output the custNum var (declared and initialized above this) just after where it is inputted, it does come out correctly. And no, I get no errors! Thanks again, sorry about before!

(Toggle Plain Text)

public static void saveBalance()
{
System.out.println("-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*");

System.out.print("Please tell me, what is the ID of the customer?");
custNum = input.nextInt();

System.out.println("Thank you!");
System.out.print("Now please tell me this customer's name?(" + custNum + "):");
Names[custNum] = input.nextLine();  //<----- Skips This!!

System.out.println(" ");

System.out.println("Thank You!");
System.out.print("Now please tell me " + Names[custNum] + "'s balance: ");
Balance[custNum] = input.nextDouble();

System.out.println("-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*");

control();
}

titaniumdecoy · Jun 13th, 2006, 8:43 PM

What class is the 'input' variable an instance of?

Jakeyman_I_Am · Jun 13th, 2006, 10:11 PM

Quote:

Originally Posted by titaniumdecoy

What class is the 'input' variable an instance of?

(Toggle Plain Text)

public static Scanner input = new Scanner(System.in);

titaniumdecoy · Jun 13th, 2006, 10:27 PM

Check out the documentation for the Scanner class. According to the docs, the nextLine() function:

Quote:

Advances this scanner past the current line and returns the input that was skipped. This method returns the rest of the current line, excluding any line separator at the end. The position is set to the beginning of the next line.

See if replacing nextLine() with next() helps.

Jun 13th, 2006, 8:03 PM	#4
Jakeyman_I_Am Newbie Join Date: Mar 2005 Posts: 14 Rep Power: 0	Also, further down in the program, the code skips the very same type line. (A input.nextLine) And I do remeber this is class being a topic my teacher covered. I just don't remember what he said.. __________________ The elder newb.

Jun 13th, 2006, 8:09 PM	#5
DaWei Resident Grouch Join Date: Jun 2005 Posts: 6,453 Rep Power: 10	Read the forum's rules/FAQ. You can learn about code tags there, and discover other things regarding the community which you wish to use as a resource. It's only the neighborly thing to do. __________________ Abstraction doesn't make it impossible to write bad code; it makes it possible to write superior code. Contributor's Corner: Grumpy on C++ Exceptions DaWei on Pointers

Jun 13th, 2006, 8:19 PM	#7
Jakeyman_I_Am Newbie Join Date: Mar 2005 Posts: 14 Rep Power: 0	I am sorry. I come from a forum with no such rules. Anyways here is the code again, and I put a comment in where it skipps. Also, if I output the custNum var (declared and initialized above this) just after where it is inputted, it does come out correctly. And no, I get no errors! Thanks again, sorry about before! (Toggle Plain Text) public static void saveBalance() { System.out.println("------------------------------"); System.out.print("Please tell me, what is the ID of the customer?"); custNum = input.nextInt(); System.out.println("Thank you!"); System.out.print("Now please tell me this customer's name?(" + custNum + "):"); Names[custNum] = input.nextLine(); //<----- Skips This!! System.out.println(" "); System.out.println("Thank You!"); System.out.print("Now please tell me " + Names[custNum] + "'s balance: "); Balance[custNum] = input.nextDouble(); System.out.println("------------------------------"); control(); } public static void saveBalance() { System.out.println("------------------------------"); System.out.print("Please tell me, what is the ID of the customer?"); custNum = input.nextInt(); System.out.println("Thank you!"); System.out.print("Now please tell me this customer's name?(" + custNum + "):"); Names[custNum] = input.nextLine(); //<----- Skips This!! System.out.println(" "); System.out.println("Thank You!"); System.out.print("Now please tell me " + Names[custNum] + "'s balance: "); Balance[custNum] = input.nextDouble(); System.out.println("------------------------------"); control(); } __________________ The elder newb.

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Jun 13th, 2006, 7:43 PM	#1
Jakeyman_I_Am Newbie Join Date: Mar 2005 Posts: 14 Rep Power: 0	Skipping input.nextLine(); Hello! I have a issue here, and to be honest I have seen this beofre, but I cannot remember how I corrected it. The problem is in this line: Names[custNum] = input.nextLine(); the problem is that it skips that line.. completely. That is the second input line in the constructor, and is followed by a system.out.println(); line. if you need more ask! Thanks! __________________ The elder newb.

Jun 13th, 2006, 7:55 PM	#2
Booooze Expert Programmer Join Date: Mar 2006 Location: Igloo Posts: 710 Rep Power: 3	(Toggle Plain Text) the problem is that it skips that line the problem is that it skips that line Obviously, that line isn't excuting to skip itself. Post more of the code.

Jun 13th, 2006, 8:11 PM	#6
Booooze Expert Programmer Join Date: Mar 2006 Location: Igloo Posts: 710 Rep Power: 3	Ok, first off a couple things: #1 - put your code in code tags if you want anyone to help. (honestly) #2- I'm looking at this page: http://www.cs.wisc.edu/~cs302/io/JavaIO_Scanner.html Are you sure your defining custNum properly? I think when you get the user input, its going to be a string. You will need to convert it. Also where is it defined? Im not big on Java, but hope this helped. Last thing, are you getting any errors when you execute the code?

Jun 13th, 2006, 8:43 PM	#8
titaniumdecoy Programming Guru Join Date: Nov 2005 Posts: 1,007 Rep Power: 5	What class is the 'input' variable an instance of?

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Programming Forums > Application Development > Java

Skipping input.nextLine();