Programming Forums > Application Development > Java

azurik · Jun 13th, 2006, 9:01 PM

I'm trying to create a simple database inside Java using seperate chain Hashing. The database stores the many products inside a grocery store. In my createDatabase method, however, it flags (using Eclipse) a warning (not syntax error) when I try to initalize the database, an array of type ArrayList<Product>:

(Toggle Plain Text)

public void createDatabase(int maxStorage, double maxLoadFactor) {
   int databaseSize = getClosestPrime((int)(maxStorage / maxLoadFactor));
   ArrayList<Product>[] chainArray = new ArrayList[newDatabaseSize];
   database = chainArray;
}
public int getClosestPrime(int num) {
   //code for finding the first number above the given integer
}

(database is an instance field of type ArrayList<Product>[])
The warning says: "Type safety: The expression of type ArrayList[] needs unchecked conversion to conform to ArrayList<Product>[]".
When I try to fix the suggested problem, a syntax error is flagged:

(Toggle Plain Text)

ArrayList<Product>[] chainArray = new ArrayList<Product>[databaseSize];

The syntax error says: "Cannot create a generic array of ArrayList<Product>".

Is there a way so that not a single warning or syntax flag is shown? I'm assuming the code would run despite the warning flag, but I'd rather remove it if at all possible.

Jimbo · Jun 13th, 2006, 9:39 PM

I had this problem once and I think it's just a bug in how generics work. For a nasty hack that'll hopefully get it working:

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private class ProductArray extends ArrayList<Product> {}; // somewhere in your class
/*...*/
ProductArray[] chainArray = new ProductArray[databaseSize]; // in your method

I don't remember if this was exactly how I did it, but it's pretty ugly either way... :o

azurik · Jun 13th, 2006, 10:19 PM

Looks like this works:

(Toggle Plain Text)

public void createDatabase(int maxPlayerNumber, double maxLoadFactor) {
    int databaseSize = getClosestPrime((int)(maxPlayerNumber / maxLoadFactor));
    class ProductArray extends ArrayList<Character> { }
    ArrayList<Character>[] chainArray = new ProductArray[databaseSize];
    database = chainArray;
}

Thx. Though it's quite unrelated to that warning, a new warning pops up that I usually see when extending many classes. I've never understood what it meant and I believe it starting popping up all over my code once 1.5 came out. It says: "The serializable class ProductArray does not declare a static final serialVersionUID field of type long". Normally, I just ignore it (sometimes I set serialVersionUID to 0, just to shut it up), but what exactly is "serialVersionUID" supposed to be representing?

EDIT: And yes, that is a quite different approach than I would have ever thought of.

Jimbo · Jun 13th, 2006, 10:35 PM

Quote:

Originally Posted by Java API

The serialization runtime associates with each serializable class a version number, called a serialVersionUID, which is used during deserialization to verify that the sender and receiver of a serialized object have loaded classes for that object that are compatible with respect to serialization. If the receiver has loaded a class for the object that has a different serialVersionUID than that of the corresponding sender's class, then deserialization will result in an InvalidClassException. A serializable class can declare its own serialVersionUID explicitly by declaring a field named "serialVersionUID" that must be static, final, and of type long...

I usually just ignore it as well, since I hardly ever use serialization when I'm doing stuff in Java...

Gumby · Jun 14th, 2006, 8:55 AM

Quote:

Originally Posted by azurik

Looks like this works:

(Toggle Plain Text)

public void createDatabase(int maxPlayerNumber, double maxLoadFactor) {
    int databaseSize = getClosestPrime((int)(maxPlayerNumber / maxLoadFactor));
    class ProductArray extends ArrayList<Character> { }
    ArrayList<Character>[] chainArray = new ProductArray[databaseSize];
    database = chainArray;
}

Thx. Though it's quite unrelated to that warning, a new warning pops up that I usually see when extending many classes. I've never understood what it meant and I believe it starting popping up all over my code once 1.5 came out. It says: "The serializable class ProductArray does not declare a static final serialVersionUID field of type long". Normally, I just ignore it (sometimes I set serialVersionUID to 0, just to shut it up), but what exactly is "serialVersionUID" supposed to be representing?

EDIT: And yes, that is a quite different approach than I would have ever thought of.

From how I understand it (and I may be off the mark here), you only need to worry about it if youre going to have concurrent access (many users running the same program at the same time, possibly changing the same data).

Jimbo · Jun 14th, 2006, 12:27 PM

if you're referring to the serialVersionID, you're off the mark

Gumby · Jun 14th, 2006, 1:31 PM

Quote:

Originally Posted by Jimbo

if you're referring to the serialVersionID, you're off the mark

so then, what IS the mark? correct my ignorance, please

edit: ah, nevermind - i didn't notice you had quoted the Java API earlier, I had just glanced at it, assumed it was a quote from a previous post, and ignored it. d'oh!

Jun 13th, 2006, 9:01 PM	#1
azurik Newbie Join Date: May 2006 Posts: 6 Rep Power: 0	Arrays with Generic Type I'm trying to create a simple database inside Java using seperate chain Hashing. The database stores the many products inside a grocery store. In my createDatabase method, however, it flags (using Eclipse) a warning (not syntax error) when I try to initalize the database, an array of type ArrayList<Product>: (Toggle Plain Text) public void createDatabase(int maxStorage, double maxLoadFactor) { int databaseSize = getClosestPrime((int)(maxStorage / maxLoadFactor)); ArrayList<Product>[] chainArray = new ArrayList[newDatabaseSize]; database = chainArray; } public int getClosestPrime(int num) { //code for finding the first number above the given integer } public void createDatabase(int maxStorage, double maxLoadFactor) { int databaseSize = getClosestPrime((int)(maxStorage / maxLoadFactor)); ArrayList<Product>[] chainArray = new ArrayList[newDatabaseSize]; database = chainArray; } public int getClosestPrime(int num) { //code for finding the first number above the given integer } (database is an instance field of type ArrayList<Product>[]) The warning says: "Type safety: The expression of type ArrayList[] needs unchecked conversion to conform to ArrayList<Product>[]". When I try to fix the suggested problem, a syntax error is flagged: (Toggle Plain Text) ArrayList<Product>[] chainArray = new ArrayList<Product>[databaseSize]; ArrayList<Product>[] chainArray = new ArrayList<Product>[databaseSize]; The syntax error says: "Cannot create a generic array of ArrayList<Product>". Is there a way so that not a single warning or syntax flag is shown? I'm assuming the code would run despite the warning flag, but I'd rather remove it if at all possible.

Jun 13th, 2006, 9:39 PM	#2
Jimbo Battle Programmer Join Date: Feb 2006 Location: Bellevue, WA, USA Posts: 769 Rep Power: 3	I had this problem once and I think it's just a bug in how generics work. For a nasty hack that'll hopefully get it working: (Toggle Plain Text) private class ProductArray extends ArrayList<Product> {}; // somewhere in your class /.../ ProductArray[] chainArray = new ProductArray[databaseSize]; // in your method private class ProductArray extends ArrayList<Product> {}; // somewhere in your class /.../ ProductArray[] chainArray = new ProductArray[databaseSize]; // in your method I don't remember if this was exactly how I did it, but it's pretty ugly either way... :o

Jun 13th, 2006, 10:19 PM	#3
azurik Newbie Join Date: May 2006 Posts: 6 Rep Power: 0	Looks like this works: (Toggle Plain Text) public void createDatabase(int maxPlayerNumber, double maxLoadFactor) { int databaseSize = getClosestPrime((int)(maxPlayerNumber / maxLoadFactor)); class ProductArray extends ArrayList<Character> { } ArrayList<Character>[] chainArray = new ProductArray[databaseSize]; database = chainArray; } public void createDatabase(int maxPlayerNumber, double maxLoadFactor) { int databaseSize = getClosestPrime((int)(maxPlayerNumber / maxLoadFactor)); class ProductArray extends ArrayList<Character> { } ArrayList<Character>[] chainArray = new ProductArray[databaseSize]; database = chainArray; } Thx. Though it's quite unrelated to that warning, a new warning pops up that I usually see when extending many classes. I've never understood what it meant and I believe it starting popping up all over my code once 1.5 came out. It says: "The serializable class ProductArray does not declare a static final serialVersionUID field of type long". Normally, I just ignore it (sometimes I set serialVersionUID to 0, just to shut it up), but what exactly is "serialVersionUID" supposed to be representing? EDIT: And yes, that is a quite different approach than I would have ever thought of.

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Jun 14th, 2006, 12:27 PM	#6
Jimbo Battle Programmer Join Date: Feb 2006 Location: Bellevue, WA, USA Posts: 769 Rep Power: 3	if you're referring to the serialVersionID, you're off the mark

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Programming Forums > Application Development > Java

Arrays with Generic Type